Thread: arrays

  1. #16
    C++ Witch laserlight's Avatar
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    Quote Originally Posted by john5754
    Here is what I got, It seems to work when I run it. See any problems?
    It should not even compile without errors since this statement is not terminated by a semi-colon:
    Code:
    int jimmy[Height * Width]
    I suggest that you post your actual code (copy and paste, if necessary), and please post it in [code][/code] bbcode tags.

    EDIT:
    Incidentally, I think that you need two arrays: the two dimensional array source and the one dimensional array destination. Alternatively, you use a one dimensional array and access it as a two dimensional array (but that seems the opposite of what you are asking for). Or, you use a two dimensional array and access it as a one dimensional array via a cast (but in practice, this should be avoided).
    Last edited by laserlight; 12-01-2008 at 11:14 AM.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  2. #17
    Registered User
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    Code:
    #include <iostream>
    #include <iomanip>
    using namespace std;
    
    
    
    int main()
    {
    	const int j=99;
    	int height=3,width=5,n,m,i,jimmy[j];
    
    	for(n=0; n<height; n++)
    		for(m=0; m<width; m++)
    		
    		{jimmy [n]=(n+1)*(m+1);
    		cout<< setw(4)<< jimmy[n];
    	}
    
    	return 0;
    }

  3. #18
    Guest Sebastiani's Avatar
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    I really don't get what you're trying to accomplish here. The code you've posted does nothing but assign some random values to the first three elements in a one-dimensional array. If you want to transform a 2-d array to 1-d, just do a cast. If you want to copy it then do the cast and use memcpy (height * width * sizeof( int )). Or, if you insist on doing it the hard way, source[ n ][ m ] == destination[ width * n + m ].
    Code:
    #include <cmath>
    #include <complex>
    bool euler_flip(bool value)
    {
        return std::pow
        (
            std::complex<float>(std::exp(1.0)), 
            std::complex<float>(0, 1) 
            * std::complex<float>(std::atan(1.0)
            *(1 << (value + 2)))
        ).real() < 0;
    }

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