HI,
I am trying to use not equal (!=) with or (||) in an if statement.
cout << "enter operator: +, -, /, *:";
cin >> oper
If (oper != '=' || '-' || '*' || '\')
cout << "Please choose +, -, /, * ";
This will not work. Is there a way to us "andor"?
Thanks Paul
if ((oper != '=') || (oper != '-') || (oper != '*') || (oper != '/'))
-Govtcheez
[email protected]
if ( oper != '+' || oper != '-' || oper != '*' || oper != '\' )
but that's kind of ugly for such a simple test, perhaps a few else ifs would suit your purpose better.
-PreludeCode:if ( oper == '+' ) /* Calculate for '+' */ else if ( oper == '-' ) /* Calculate for '-' */ else if ( oper == '*' ) /* Calculate for '*' */ else if ( oper == '/' ) /* Calculate for '/' */ else cout<<"Please choose +, -, / or * "<<endl;
My best code is written with the delete key.
>>PROGRAM: A magic spell cast over a computer allowing it to turn one's input into error messages.
Funny!LOL
Blue
if ((oper<42&&oper>47)||oper!=44||oper!=46) ....
a needlessly complicated way to do it
Last edited by ygfperson; 02-13-2002 at 06:34 PM.
How about using a switch, it it not 'elegant' programing?
switch( oper )
{
case '+':
//stuff
break;
case '-':
//more stuff
break;
etc
etc
default: //covers all other possibilities
break;
}
Switch is ugly and annoying.
