Hello
Is it possible to do the following (without template argument list):
with this code:Code:Registry::Inside::Type some_type;
Ive been wondering if this is possible because I want to keep datatypes nicely organized in same classes so that I could do:Code:template<class T> struct Registry { typedef std::map<std::string, T> Type; struct Inside { typedef std::string Type; }; };
Many thanks in advance!Code:Registry::Inside::Type some_type; Registry<std::string>::Type some_other_type;