Thread: recv data with sockets

  1. #1
    Registered User
    Join Date
    Oct 2008

    recv data with sockets


    Im not sure if this post should be in this board or the network programming board, anyway here is my question.

    I am coding a server program with sockets on linux and when I got to the recv part I noticed a unexpected behaviour.

    Here is the code for the recv data part:
    //read some data
    char recvBuf;
    	error = recv(new_fd, &recvBuf, 1, 0);
    	switch (error)
    	case -1:
    		cout << "[ERROR] recieving data" << endl;
    		recvBuf = '.';
    	case 0:
    		cout << "Connection to client was lost" << endl;
    		recvBuf = '.';
    		cout << recvBuf;
    } while (recvBuf != '.');
    Now when I run this and connect to the server with telnet, the server waits until I press ENTER until it writes recvBuf to the screen. But if I press '.' the program ends without me pressing ENTER.

    How can the text I type in telnet be saved and then printed, shouldn't the recvBuf be overwritten for every new data the server reads ?

    Thanks for helping me understand this.

  2. #2
    and the hat of int overfl Salem's Avatar
    Join Date
    Aug 2001
    The edge of the known universe
    The output is probably buffered until it sees a newline.
    Try cout.flush()
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  3. #3
    Registered User
    Join Date
    Oct 2008

    Thumbs up

    Thanks that worked.

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