Reading terminal arguments

Quote:

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Originally Posted by DenKain

Also, what do you mean that my argc check is broken?

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Just that. You noticed how it didn't work, just now? It claimed that you didn't give any arguments, when in fact you gave two. What do you think that if(argc==2) does, and why isn't it what you want?

Alright if argv[0] = appName and argv[1] = -t and argv[2] = input.....then what the heck does argc stand for? I thought it was a count of the number of arguments the user entered? If so then yes I did it incorrectly. When I set it to if argc==0 then it came up with this error when I ran the program :"Segmentation fault".

I thought I made it clear in my second response. argc is the number of arguments in argv. Like any other array, you can access up to argv[argc-1].

Post your whole code. I don't see why a segfault would have come up.

Quote:

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Originally Posted by DenKain

Alright if argv[0] = appName and argv[1] = -t and argv[2] = input.....then what the heck does argc stand for? I thought it was a count of the number of arguments the user entered? If so then yes I did it incorrectly. When I set it to if argc==0 then it came up with this error when I ran the program :"Segmentation fault".

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Why yes, it is a count of the arguments. In this case there are three arguments (appName, -t, and input).

That is the whole code.

Oh I see the issue.

Quote:

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Originally Posted by DenKain

When I set it to if argc==0 then it came up with this error when I ran the program :"Segmentation fault".

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EDIT:

Well I will pick this up tomorrow as I have to head out to meet friends for dinner and a movie.

I hadn't used this in a while... but I used to like to use this construct for C++ programs when I was first using C++.

CPPMain.h

Code:

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#ifndef MAIN__INCLUDE_ONCE_EVER__
#define MAIN__INCLUDE_ONCE_EVER__ 1
#include <vector>
#include <string>

typedef std::vector<std::string> Argv;

int Main(const Argv &);

int main(int argc, char **argv)
{
  Argv v;

  for(register int i = 0;i < argc;++i)
    v.push_back(argv[i]);

  return Main(v);
}
#endif

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Example:

Code:

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#include "CPPMain.h"

int Main(const Argv &argv)
{
  // Your code goes here...

  return 0;
}

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I dunno... It has its pros and cons but it may help you in your project.

I probably could have done a quick sample of how to use the Main() function...

Example:

Code:

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int Main(const Argv &argv)
{
  for(int i = 0; i < argv.size(); ++i)
    if(argv[i] == "-t")
    {
      // whatever
    } else if(argv[i] == "-t")
    {
      // whatever
    }

  return 0;
}

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Sorry but the example at the bottom of this link was what I ended up understanding and using. Although I broke it up into a separate class to parse out the arguments for me.

http://www.phon.ucl.ac.uk/courses/sp...c/lesson11.htm