Thread: DOS Program

Hey, I've written my program it does what I want it to do. Until I try and run it in dos. Then I get this irratating message "this program cannot run in dos." My question is, is there anyway to write a dos program using VC++ 6.0.

Any help is appreciated
Jon
[email protected]

sure you can make a DOS program in Visual C++
you can make new project (you should choose win32 console application)
console program is suitable for DOS envirnment.

if you have the right compiler... i think borland had a strictly dos compiler it was something like version 3 or 3.3 somthing like that. but then again Dev-C++ is a good compiler and if you create a new project it will ask

create new... Windows , Dos , Win32 , Dll , or empty project

you should select eother DOS or WIN32 they both should be compatible with you "project" and if WIN32 isnt DOS should work no q's asked if you dont have DEV-C++ get it HERE

DJGPP is extremely excellent DOS only compiler. You can get it at www.delorie.com

I've only had one problem with DJGPP. The assembly isn't the standard assembly code. It's a weird type. There is a link to a regular to weird chart somewhere in the boards. It is either AT&T is regular or IBM is, I don't remember.

If you want to use graphics in DJGPP, a good site to go to is www.brackeen.com

I've tried a win32 console app in VC++. Still got the message "this program cannot run in DOS mode". I downloaded DevC++ and can't get my program to compile without errors. It compiled free of errors in VC++.

Any help is appreciated
Jon
[email protected]

post your code

Okay guys here is the code. I found it elsewhere on this board, and modified it to fit my needs.

#include<iostream>
#include<conio.h>

using namespace std;

void GetPassword( char* entry );

void main( void )
{

char password[10] = "admin";
char entry[10] = "";

do{

cout << "\nEnter password: " << flush;


GetPassword( entry );

}while(strcmp(entry, password));

}

void GetPassword( char *entry )
{
int i = 0;
char ch;

while( 1 )
{
while( !kbhit() ); //** pause until kentered

ch = entry[ i++ ] = (char)getch();

putchar( '*' );

if( ch == 13 ) //does not like '\n or '\0'
{
entry[i-1] = '\0';
break;
}
else if( i == 9 )
{
entry[i] = '\0';
break;
}
}
}


Any help is appreciated
Jon
[email protected]