the problem here is that i have an array of chars
and i want to create a function that returns this array so something likeCode:char exampleArray[50];
but this wont work as it cannot convert from char[30] to char any ideas?Code:char getCharArray() { return exampleArray; }
Many Thanks
You cannot return an array from a function by value. You can return it by reference though. But then you would be using a local variable that had already gone out of scope. Either malloc it in the function and free it outside the function, or pass an array to the function by reference.
Last edited by robwhit; 09-18-2008 at 08:28 AM.
...or just use an std::vector.
Code:#include <cmath> #include <complex> bool euler_flip(bool value) { return std::pow ( std::complex<float>(std::exp(1.0)), std::complex<float>(0, 1) * std::complex<float>(std::atan(1.0) *(1 << (value + 2))) ).real() < 0; }
Sorry im not that experience with c++ here is my code that im trying to get working.
Code:class charArray { public: charArray() { memset( sampleArray, " ", 30); } void setSampleArray(char x[]){ strcpy( sampleArray, x); } char getSampleArray() { return sampleArray; } // << problem protected: char sampleArray[30]; };
Wouldn't it be possible to do:
A char and a pointer-to-a-bunch-of-chars is a different thing.Code:const char* getSampleArray() const { return sampleArray; }
I might be wrong.
Quoted more than 1000 times (I hope).Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
As stated, C does not allow assignment of arrays, and returning an array that you can't assign to something is pretty pointless [what I'm trying to say, is that arrays can not be returned, because you can not "give" the returned array to anything].
You can do other things, such as return the address of it, or you can pass in an array to copy it into, or even create a copy dynamically using new and free it with delete. Which is best for you depends on what you want to do with the array.
--
Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
Isn't this:
what you want?Code:const char* getSampleArray() const { return sampleArray; }
Won't these work?
orCode:charArray ca; char *arr; arr = ca.getSampleArray(); cout << arr[0] << arr[1]; //outputs two spaces
Of course you could use string instead of char[]Code:charArray ca; char array[30]; strcpy (array, ca.getSampleArray()); cout << arr[0] << arr[1]; //outputs two spaces
worked for me thank you very much for your replies.Code:const char* getSampleArray() const { return sampleArray; }
Why not use an std::string instead of a char array?
"I am probably the laziest programmer on the planet, a fact with which anyone who has ever seen my code will agree." - esbo, 11/15/2008
"the internet is a scary place to be thats why i dont use it much." - billet, 03/17/2010
that is wrong, " " is the address of a string that holds a space, terminated with a zero. That is almost certainly not matching what you actually want to fill your string with [and you should get a warning or error for it].Code:memset( sampleArray, " ", 30);
--
Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
C? Since when is this C?Originally Posted by matsp
Anyway, to point something else out.
You have an array of chars, char[30], and then try to return char. See the problem? The types do not match. You are telling the compiler the function is returning something else than you are actually returning.
That mentioned, a solution was already given, so you don't need to change anything. Just giving you some information on why it failed.
