Thread: C++ Need Help writing a Small program

Wavelenght of visible light fall approximately into the range 0.4--0.7 microns. The Table below shows the relationship between wavelenght and color.

Write a program that inputs a wavelenght and then displays the associated light color. If the wavelenght is shorter than 0.4 microns or longer than 0.7, display the message wavelenght outside visual range.
clasiffy boundary wavelenghts as the lower-wavelenght color.
For example, label a wavelenght of 0.424 microns as violet.

Color_________________________________Aproximate wavelenght range(microns)
------------------------------------------------------------------------------------------------------------
Violet________________________________________0.40 0--0.424
Blue_________________________________________0.424--0.491
Green_______________________________________0.491--0.575
Yellow_______________________________________0.575--0.585
Orange______________________________________0.585--0.647
Red_________________________________________0.647--0.700




I tried it but with no success, i had like 12 errors.

And those 12 errors are?

I don't know exactly where I'm wrong, I'm lost I'm a beginner. can you Please Post the Write Code. Thanks

Code:

//robert
include <iostream>
using namespace std;

Int main (void) {

float w;
cout << "Input Wavelenght " ;
cin >> w ;

If (w > .7) {
cout " wavelenght outside visual range " ;

} else if (w > .647 ) {
cout << " red " ;

} else if (w > .585 ) {
cout << " orange " ;


} else if (w > .575 ) {
cout << " yellow " ;

} else if (w > .491 ) {
cout << " green " ;

} else if (w > .424 ) {
cout << " blue " ;

} else if (w > .400 ) {
cout << " violet " ;


}else{

cout<< " out of range " ;

return 0 ;

}

You need to put code inside a main() function.

Indeed it is -- I managed to completely miss that the first time. "If" is also a problem.