pointers

[manzoor]

Look at my last post

#include <iostream>
#include <iomanip>

using std::cout;
using std::endl;
using std::dec;

int main()
{
	int number = 25;

	int* pNumber = &number;

	cout << endl
		<< dec << pNumber << endl;

	return EXIT_SUCCESS;
}

[matsp]

Your hard-disk is full?

--
Mats

[manzoor]

Oh lol,


Well, one drive is full,

[matsp]

Oh lol,


Well, one drive is full,

In this case, you can probably overcome the problem by setting the environment veriable temp to something else - I usually set it to x:\temp wher x is some drive that has lots of space. You can either restart your dev environment from a command prompt after "set temp=x:\temp" or configure your system settings (My computer -> Properties -> Advanced -> Environment Variables). You may want to set the environment variable "TMP" as well.

--
Mats

[manzoor]

Okay thanks,

One more question to ask, prior to the code

the pNumber should return the address in decimal but it doesnt why ?

[anon]

the pNumber should return the address in decimal but it doesnt why ?

That's how pointers are displayed. std::dec probably only applies to how real numeric types are output.

To display it as an integer (you don't need std::dec), you'll need a cast:

reinterpret_cast<int>(pNumber)

And lastly an observation: you use cout, endl and dec just once, yet went through all the trouble to type the using directives ... for what?

[matsp]

To display it as an integer (you don't need std::dec), you'll need a cast:

reinterpret_cast<int>(pNumber)

Note that a pointer is not guaranteed to fit in an int - it may be twice as big (or even larger, at least in theory).

--
Mats

[Elysia]

On Windows, it's possible to include windows.h and use INT_PTR. It's guaranteed to fit.

[anon]

Then cast to size_t?