Thread: 3D vector

[Note that this is in that case a bug in the compiler, really]

The standard says the following:

3 After name lookup (3.4) finds that a name is a template-name, if this name is followed by a <, the < is
always taken as the beginning of a template-argument-list and never as a name followed by the less-than
operator. When parsing a template-id, the first non-nested > is taken as the end of the template argument- list rather than a greater-than operator. [Example:

Code:

template<int i> class X { /* ... */ };
X< 1>2 > x1; // syntax error
X<(1>2)> x2; // OK
template<class T> class Y { /* ... */ };
Y< X<1> > x3; // OK
Y<X<6>> 1> > x4; // OK: Y< X< (6>>1) > >     <----------

This does not concern the shift operator, but it (line <-------) seems to indicate that the end of two nested templates must be separated by a blank space..

ps: how do I color a line in my thread?