Thread: Fix Please

Okay i can't fix it with the limited knowledge i have... please someone help

Code:

#include <iostream>

using namespace std;

int main()
{
    int number;
    cout<<"Wecome to the attempted C++ \n Press enter to continue.";
    cin.get();
    
    cout<<"Choose a number from 1 to 10 and \n you will be rewarded if you guess correctly.";
    cin>> number;
    cin.ignore();
    
    if (number)!(1&&2); { cout<<"Try again!"; 
    }
    
    else if (number<2); {cout<< "You win ....";
    cin.get(); 
    cout<<"Nothing.";}
    cin.get();
}

errors
E:\Programs\Programing\Programs\Guessing Game.cpp: In function `int main()':
E:\Programs\Programing\Programs\Guessing Game.cpp:18: error: expected primary-expression before "else"
E:\Programs\Programing\Programs\Guessing Game.cpp:18: error: expected `;' before "else"

Execution terminated

>> if (number)!(1&&2);
This line has a syntactic error and a semantic error. Lookup how to use && in your book/tutorial and pay attention to the difference between the example and your code. Then lookup the syntax for the if /else if statements.

Daved, that not the error that the compiler found but i fixed what you said,

what do i do with the "else if" cause i can't understand what i'm missing

Code:

#include <iostream>

using namespace std;

int main()
{
    int number;
    cout<<"Wecome to the attempted C++ \n Press enter to continue.";
    cin.get();
    
    cout<<"Choose a number from 1 to 10 and \n you will be rewarded if you guess correctly.";
    cin>> number;
    cin.ignore();
    
    if (number)!(1||2); { cout<<"Try again!"; 
    }
    
    else if(0<number<2); {cout<< "You win ....";
    cin.get(); 
    cout<<"Nothing.";}
    
    else {cout<<"Between 1 and 10 please"; }
    cin.get();
}

hehe wow you're great, you will be a great parent!

Code:

if( condition )
{ // these are optional if only one statement follows.
    dosomething;
}
else if( condition )
    dosomething;
else
    dosomething;

in your case :

Code:

if (number)!(1||2);

This doesn't conform to the above. Your if condition must be contained in ( )'s. There should NOT be a ';' after the if statement.

I solved it YES!!!!!!!!!!! Thanks Elysia, can you by anychance add me on msn? ([email protected])

Try out this sick game.
I could sell this on the Black market :O :P

Code:

#include <iostream>

using namespace std;

int main()
{
    int number;
    cout<<"Wecome to the attempted C++ \n Press enter to continue.";
    cin.get();
    
    cout<<"Choose a number from 1 to 10 and \n you will be rewarded if you guess correctly.";
    cin>> number;
    cin.ignore();
    
    if (!(1||2)) { cout<<"Try again!"; 
    }
    
    else if(number>0 && number<2) {cout<< "You win ....\n...Nothing";}
    
    else {
         cout<<"Between 1 and 10 please"; }
    cin.get();
}

if (!(1||2))
This is always false. Use the equality operator and actually make a comparison with your number.

if (number>0 && number<2)
While not as straight forward, it's right. The only number more than zero and less than two is one. It's also lame, because the game cheats. Use random numbers from a generator, Nestor.

Okay let me explain to you my logic, when you play a game the better the ods the more you want to play it, that basically it, but you are right, it should be one number only.

You catch all mistakes :P

anon i swear i burst out laughing when i read what you wrote haha "is this program supposed to be annoying" HAHAHAHHAHAHAHA!
good one

Originally Posted by citizen

if (!(1||2))
This is always false. Use the equality operator and actually make a comparison with your number.

if (number>0 && number<2)
While not as straight forward, it's right. The only number more than zero and less than two is one. It's also lame, because the game cheats. Use random numbers from a generator, Nestor.

Listem men, i started programing yesterday....well today 1 am, i havn't gotten as far as a random numbers generator:P but if you are bored you can explain how it can be a random number generator if the computer can't think for itself?