Do the member initializers of a constructor run in the order that they are listed?
For example, can j reliably initialize to n + 1 in this example?
Code:struct s { int i; int j; s(int n) : i(n), j(i + 1) {} };
Do the member initializers of a constructor run in the order that they are listed?
For example, can j reliably initialize to n + 1 in this example?
Code:struct s { int i; int j; s(int n) : i(n), j(i + 1) {} };
No, the construction oddly enough is actually done in the order that the member variables are declared.
What you posted would work, but this would fail:Code:struct s { int j; int i; s(int n) : i(n), j(i + 1) {} };
My homepage
Advice: Take only as directed - If symptoms persist, please see your debugger
Linus Torvalds: "But it clearly is the only right way. The fact that everybody else does it some other way only means that they are wrong"
