array

[Unregistered]

Hi there,

How to allocate a 2 dimension array using "new" operator?
How to pass a 2 dimension array to a function?
Is pointer always 4 bytes long or depends on system?


Thank you

[Unregistered]

type ** name;
name = new type* [xlength];
for(int i = 0; i < xlength; i++)
{
name[i] = new type[ylenght];
}


//passing 2D array to function
foo(name);


to my knowledge pointers are always 4 bytes long.

[ygfperson]

does a command like

char dummy[390][435906];

allocate 390*435906 bytes?(give or take a few)

[Stoned_Coder]

does a command like

char dummy[390][435906];

allocate 390*435906 bytes?(give or take a few)

well that would be 390 pointers (4 bytes each) to 390 different allocated areas of 435906 bytes. So i guess the minimum memory being allocated is (390*4)+(390*435906) = about 167Mb