How can a binary get its working dir at run-time?

Quote:

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Originally Posted by meili100

Thanks, but

Code:

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/proc/self/exe -> /home/me/myproject/bin/myprog

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is a link.
How to get the

Code:

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/home/me/myproject/bin/myprog

---

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You could always parse ls -l or something . . . .

. . . or, if you can convince "open" or whatever not to follow symbolic links, you could just read the file directly.

Quote:

---

Originally Posted by meili100

Thanks, but

Code:

---

/proc/self/exe -> /home/me/myproject/bin/myprog

---

is a link.
How to get the

Code:

---

/home/me/myproject/bin/myprog

---

---

Ok, so you probably need to use opendir()/readdir()/closedir() to open/read/close the directory entry then. Unfortunately, you won't be able to spawn a process and use something like a "ls | awk ..." or "ls | sed ...", since you would then get the path to "ls", rather than your application, which I assume is what you are actually after [although I suppose the stuff is also in a numbered process /proc/<pid>/exe (or similar) directory, so I suppose that would be possible to use for such scripting tricks].

Edit: Note that you would have to do (pseudo-code)

Code:

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x = opendir("\proc\self");
while(readdir(dirinfo))
{
  if (dirinfo.fname == "exe")
  {
      getlinkcontent();
      break;
  }
}
closedir(x);

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Mats