Array of pointers

**rocketman50** · 03-19-2008

Hi, im using visual c++ and I am getting run time errors whenever i try this problem.

What i am trying to do it create an array of linked lists. So for example in array[x][y] I would like to store the node at the head of the list.

Could someone advise me how to declare this array and how to use it / pass it to functions?

Thank you

- this is a piece of code im using now. This function takes the pointerarry, an x-y coordination and number to put in the linked list.

Code:

void createlist(int x, int y, int value, nodeptr *pointerarray[9][9]){

	nodeptr hdList;
	hdList = new node;
	hdList->number = value;
	hdList->next = NULL;
	pointerarray[x][y] = &hdList;
}

**anon** · 03-19-2008

It looks like you are trying to store the address of the local pointer, rather than a pointer to the allocated node.

Perhaps this works better:

Code:

void createlist(int x, int y, int value, nodeptr pointerarray[9][9]){

	nodeptr hdList;
	hdList = new node;
	hdList->number = value;
	hdList->next = NULL;
	pointerarray[x][y] = hdList;
}

**rocketman50** · 03-19-2008

great man! thank you. It seems to be doing what I want now

**Elysia** · 03-19-2008

Suggestion: Avoid typedefing type* things because it makes the code less readable, especially when used wrong. I see not harm in typing type* instead of typeptr.

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