Thread: Why Does The destructor destroy the original object??

Ok is this solution correct??

Code:

#include <string.h>
#include <iostream.h>

class str
{
	char *s;
	public:
		str(){}
		~str()
		{
			delete []s;
		}
		str(str &p)
		{
			memcpy(this,&s,sizeof(s));
			s=new char[strlen(p.s)+1];
		}
		void getdata(char*);
		void putdata();
		friend int xstrlen(str);

};
int xstrlen(str A)
{
 int l=0;
 while(*A.s)
 {
	l++;
	A.s++;
 }
 return l;
}

void str::getdata(char* p)
{
   s=new char[strlen(p)+1];
   strcpy(s,p);

}
void str::putdata()
{
	cout<<s<<endl;
}

int main(void)
{
 str A;
 A.getdata("string");
 A.putdata();


 xstrlen(A);
 A.putdata();

 return 0;
}

if yes! then now could you please explain me what am i doing when i call the xstrlen()??the control passes to copy constructor?but why??that i dont know?now please anybody explain me!what exactly is happening?