Thread: Why Does The destructor destroy the original object??

Hello,
this is also one of the weirdest problem that i came across and even you would agree to it..the code is

Code:

#include <string.h>
#include <iostream.h>

class str
{
	char *s;
	public:
		~str()
		{
			delete s;
		}
		void getdata(char*);
		void putdata();
		friend int xstrlen(str);

};
int xstrlen(str A)
{
 int l=0;
 while(*A.s)
 {
	l++;
	A.s++;
 }
 return l;
}

void str::getdata(char* p)
{
	s=new char[strlen(p)+1];
	strcpy(s,p);
}
void str::putdata()
{
	cout<<s<<endl;
}

int main(void)
{
 
 str A;
 A.getdata("string");
 A.putdata();

 xstrlen(A);

 A.putdata();


 return 0;
}

Ok the 2nd A.putdata() prints garbage because when we come out of xstrlen the destructor gets called and destroys the object. That's fine but why does it destroy the original A object even though i have used call by value?? can anybody answer this to me??