for loops

[Stephanie]

I can not figure out how to set my for loop up so that it will relay back whether or not the number entered by the user is perfect, deficient, or abundant. This is what I have so far. I know it needs a lot of work but I am stuck...

# include <stdio.h>
main()
{
int num=0, count=1, sum=0;
char perfect, abundant, deficient;

perfect==((count % num) && (count==sum));
abundant==((count % num) && (count < sum));
deficient==((count % num) && (count > sum));

printf("This program will ask you to enter some numbers.\n");
printf("Number Type\n");
printf("------ ----\n");

for(count=1; count <= 20; count++)
printf("%d ",count);
scanf("%d", &count);

[Shiro]

Don't know exactly what you mean. But I'll give it a try: you're for-loop should contain something like this.

scanf ("%d", &num);

perfect = (count % num) && (count==sum); 
abundant = (count % num) && (count < sum); 
deficient = (count % num) && (count > sum);

if (perfect)
    printf ("num is perfect\n");
else if (abundant)
    printf ("num is abundant\n");
else /* deficient == TRUE */
    printf ("num is deficient\n");

Ofcourse the calculation of perfect, abundant and deficient is not needed, it could be done in the if-condition. This would save both space and time.