dice problem

[goran00]

i am trying to make a program to keep running (rolling of two dice) until the total of the two is 10 or 11.
which function and how can i use it to make the program stop running when the total of two dice equals 10 or 11.
i tried with the while loop but that didn't seen to work.

[tabstop]

You may actually want to use a do-while loop here, so that the dice get rolled at least once. But either way should work. Post what you have.

[goran00]

here is what i have. i can not figure out how to make the program stop running when (the point) or 7 are the newTotal.
i know how to do the count loops, but how do i take the count out.

insert

while (count<5){

		
		rollADie=rand()%6+1;
		rollADie2=rand()%6+1;
		newTotal=rollADie+rollADie2;

		printf("The new randon is %i\n",newTotal);

		if (newTotal ==thePoint)
		{printf("You win \n");
		break;}
		else if (newTotal==7)
		{	printf("You loose\n");
		break;}
		else 
		{printf("Nothing\n");}

		count++;}

[tabstop]

So if you want to stop when newTotal is the point or 7, why don't you do

do
    /* all your dice rolling */
while (newTotal != 7 && newTotal != thePoint)
/* Check results here */

Remember de Morgan's law: -(x or y) = -x and -y.

[whiteflags]

var faces
while faces != 10 AND faces != 11
   do reroll
end while

The rest is basically arithmatic. And might I recommend that you use

rand() % (6 - 1) + 1

because otherwise you would occassionally get 7 on a die.

[goran00]

i tried that
and this is what the compiler gives me
fatal error C1075: end of file found before the left brace '{' at (the file name)

[tabstop]

var faces
while faces != 10 AND faces != 11
   do reroll
end while

The rest is basically arithmatic. And might I recommend that you use

rand() % (6 - 1) + 1

because otherwise you would occassionally get 7 on a die.

? % is remainder, so rand()%6 could only give 0, 1, 2, 3, 4, or 5.

[goran00]

i did that and still the same problem

[tabstop]

i tried that
and this is what the compiler gives me
fatal error C1075: end of file found before the left brace '{' at (the file name)

When you tried ... what? The do-while? You still need to enclose the statements in the loop in curly braces.

[goran00]

when i click the error this is the line it takes me to
#include <stdio.h>

[goran00]

i got the loops, the curly braces and still the same problem

[whiteflags]

? % is remainder, so rand()%6 could only give 0, 1, 2, 3, 4, or 5.

Hm, well that's right. But a normal six sided die does not have a zero face, so some effort to squeeze the range of rand into 1 to 6 inclusive is necessary. That's pretty much the only way I know how to do it also.

[goran00]

thats good. it works not its giving me another error
error C2061: syntax error : identifier 'rollADie2'
what does that mean

[tabstop]

Post your code. You do have a main() function, right? And you have all your variables declared somewhere, right?

[goran00]

include <stdio.h>
#include <stdlib.h>
#include <time.h>

main(){
	int rollADie;
	int rollADie2;
	int comeOutRoll;
	int count;
	int thePoint;
	int newTotal;

	srand(time(NULL));
	count=0;
	thePoint=0;

	rollADie=rand()&#37;6+1;
	rollADieA=rand()%6+1;
	comeOutRoll=rollADie+rollADie2;

	printf("%i\n",rollADie);
	printf("%i\n",rollADie2);
	printf("%i\n",comeOutRoll);

	if (comeOutRoll == 7)
	{printf("Winner\n");}
	else if (comeOutRoll == 11)
	{printf("Winner\n");}
	else if (comeOutRoll ==2)
	{printf("You loose\n");}
	else if (comeOutRoll ==3)
	{printf("You loose\n");}
	else if (comeOutRoll ==12)
	{printf("You loose\n");}


	else 
	{printf("You might have a chance \n");
	thePoint=comeOutRoll;
	printf("The point is %i\n",thePoint);
	do

		rollADie=rand()%6+1;
		rollADie2=rand()%6+1;
		newTotal=rollADie+rollADie2;

		printf("The new random is %i\n",newTotal);

		if (newTotal ==thePoint)
		{printf("You win \n");}
		else if (newTotal==7)
		{printf("You loose\n");}
		else 
		{printf("Nothing\n");}

		count++;
		while (newTotal != thePoint && newTotal != 7);


	}


	printf("The answer worked\n");
	system ("Pause");
}