Thread: displaying a array to output

Do the test before you print the character.

Still having a problem. Heres how I tried to change the code:

Code:

        printf("%c", sequence[0]) ;
        for(x = 1; x<strlen(sequence) ; ++x) // print 60 letters per line.
            {                                        
                 if((x%60 == 0) && (x != 0))
                    {
                        printf("\n") ;
                    }
                 else 
                    {
                    printf("%c", sequence[x]) ;
                    }
            }

I even tried starting a x=0 in the for loop with the same conditional for the if loop

And you added an else clause why? Now sequence[60], sequence[120], etc will never print.

Thank you tabstop for the help. Everything works fine. Sorry for the frustration. I must reiterate that I am barely a novice to programming.