Checking value of one character in array

[System_159]

Very simple problem here, I just don't understand why this isn't working.

if(current_dir[(strlen(current_dir) - 3)] == '.')

given that current_dir is:
/cygdrive/c/dirent_tests/fssw.exe

the if statement should be true, right? No matter what I do it's always false, what's up?

-System_159

[tabstop]

There are 33 characters + a '/0', so strlen gives 33. The '.' character is current_dir[29], so it looks like you should subtract 4.

[brewbuck]

There are 33 characters + a '/0', so strlen gives 33. The '.' character is current_dir[29], so it looks like you should subtract 4.

Also, this code seems to assume that all extensions are three letters long. Better to use strrchr() to locate the last '.' in the string. Everything to its right is the extension.

[System_159]

Also, this code seems to assume that all extensions are three letters long. Better to use strrchr() to locate the last '.' in the string. Everything to its right is the extension.

The only extensions I'll be using are 3 characters long, which is why I've done it this way.

tabstop, thanks for pointing that out(again). Hopefully from now on I'll remember the damn '/0' !

[brewbuck]

The only extensions I'll be using are 3 characters long, which is why I've done it this way.

"The only bullets I'll be firing are blanks, so that's why I'm pointing the gun at my head."

[Elysia]

There are 33 characters + a '/0', so strlen gives 33. The '.' character is current_dir[29], so it looks like you should subtract 4.

I believe that's '\0'.
'/' is not an escape character to my knowledge.

[ttaix]

I believe that's '\0'.
'/' is not an escape character to my knowledge.

You're right,absolutely

[foxman]

By the way, this is not due to the fact the last character of a string is '\0' but because the first element of an array is at index 0.