Thread: Printing the data in the right format

Originally Posted by matsp

Some slight modification to the format:

Code:

#include <stdio.h>

int array[] = 
{0x00000000,
 0x1fa42c33,
 0x1c202c33,

 0x189c2c33,
 0x15182c33,
 0x11942c33,

 0x0e102c33,
 0x0a8c2c33,
 0x07082c33,

 0x03842c33,
 0x00002c33,
 0x50dc2c32,
};


union timestamp {
   int tdate;
   struct {
      unsigned day:5;
      unsigned month:4;
      unsigned year: 4;
	  unsigned :1;
      unsigned seconds: 17;
   } bits;
};

void swap(unsigned char &a, unsigned char &b)
{
	unsigned char t;
	t = a;
	a = b;
	b = t;
}

void byteswap(int &t)
{
	unsigned char *x = (unsigned char *)&t;
    swap(x[0], x[3]);
	swap(x[1], x[2]);
}

int main(void)
{
	int i;
	timestamp tt;
	for(i = 1; i < 12; i++)
	{
		tt.tdate = array[i];
		printf("%04d-%02d-%02d %02d:%02d:%02d\n", tt.bits.year+2001, tt.bits.month, tt.bits.day, 
				tt.bits.seconds / 3600, (tt.bits.seconds % 3600) / 60, tt.bits.seconds % 60);
	}
	return 0;
}

Gives this output:

Code:

2007-01-19 09:00:00
2007-01-19 08:00:00
2007-01-19 07:00:00
2007-01-19 06:00:00
2007-01-19 05:00:00
2007-01-19 04:00:00
2007-01-19 03:00:00
2007-01-19 02:00:00
2007-01-19 01:00:00
2007-01-19 00:00:00
2007-01-18 23:00:00

Thanks Mat for the code, one last thing where are you exactly calling the "byteswap" function. I don't see a call to that function in either main or outside main. Thanks once again

Originally Posted by matsp

No, because my first attempt was a bit "strange", so I tried swapping the bytes around, but it didn't make any more sense that way, so I shuffled it around in a different way, and that appears to work. I'm still a bit suspicious that the time counts down instead of up, but I guess that's just how it happens to be.

--
Mats

So it means i dont need to have those two functions, i can just simply copy the first 4 bytes into the time_stamp union and i wil be alright?