I have an int i, say 6473, and I want to store each digit separately in an array, like so:
array[0] = 6;
array[1] = 4;
array[2] = 7;
araay[3] = 3;
How can I do this?
thx
I have an int i, say 6473, and I want to store each digit separately in an array, like so:
array[0] = 6;
array[1] = 4;
array[2] = 7;
araay[3] = 3;
How can I do this?
thx
What have you tried?
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
What is the problem, I would ask? You specifically mention an array - is the problem that you do not know how to create or declare an array?
I know how to declare an array, I just don't know how to split an int into an array.
Ah, now I understand. So basically, each digit into its own array. For that I would ask if you actually answer laserlight's question.
I could also provide some insight - how would you do it mathematically in the real world?
No that's not what I meant.
Think of it this way, ignore the whole array part, the question really is:
How would I access each individual digit of the number: 45656
i.e. what would I have to do to access the 4?
Suppose you divide the number by 10. What is the remainder?How would I access each individual digit of the number
Look up a C++ Reference and learn How To Ask Questions The Smart Way
Ah k, in the end I've just decided to convert to a string
Admittedly, it's possible without a string, but a bit tricky. Here's an example!
num1 = 5, num2 = 4, num3 = 3, num4 = 2, num5 = 1Code:const int mynum = 12345; int num1 = ( mynum - (mynum / 10 * 10) ) / 1; int num2 = ( mynum - (mynum / 100 * 100) ) / 10; int num3 = ( mynum - (mynum / 1000 * 1000) ) / 100; int num4 = ( mynum - (mynum / 10000 * 10000) ) / 1000; int num5 = ( mynum - (mynum / 100000 * 100000) ) / 10000;
Might I suggest sprintf()...
Code:char str[12]; int num = 12345; sprintf( str, "%d", num );
Actually, it's not very difficult to do your own as long as you store the string from the back. But obviously much less code to use sprintf() [at least of code "that you write yourself"].
--
Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
Arguably, the easiest way is to convert to string first, then take each element and covert back to integer again. Although the OP did specify that it was converted to a string in the end.
