Need help on this program!

char != double.
Don't mix types.
If you read a double, read into a double, NOT a char.
If you assign a double, assign it to a double, NOT a char.
name in the struct is declared as char, so re-think your design!

Oh, I see what you mean I think.

Like this?:

Code:

---

fprintf(outputFile, "%f -- Reliability %c\n", circuits[n].name);
fprintf(outputFile, "%f -- Cost %c\n", circuits[n].name);

---

I quoted all of those statements. Also notice in those two lines you have TWO %, but only one argument is passed. Now that's even worse.
Go read up a little on fprintf and the other lines where you assign doubles to char.

Here is what I have now, can anyone help me with inputting the text file?

Code:

---

#include <stdio.h>
#include <stdlib.h>

#define NUMBER_OF_CIRCUITS 5

typedef struct{
        char name;
        float reliability;
        float cost;
} circuit;

int main()
{

circuit circuits[NUMBER_OF_CIRCUITS];
FILE *inputFile = fopen("circuitreliability.txt", "r");
FILE *outputFile;
float reliability;
float cost;
int n = 0;
int index;
for(n = 0; n < NUMBER_OF_CIRCUITS; n++)
{
      circuits[n].circ = 0;


fscanf(inputFile, "&#37;d-%f-%f", &index, &reliability, &cost);
                circuits[index].reliability =reliability;
        circuits[index].reliability =cost;
 
fprintf(outputFile, "%d -- Reliability %f\n", circuits[n].name, circuits[n].reliability);
fprintf(outputFile, "%d -- Cost %f\n", circuits[n].name, circuits[n].cost);
}
return (0);
}

---

In the text file, circuit A is denoted by 0, B by 1, C by 2, D by 3, E by 4.

The text file's contents is as follows, from what I've been told:

0-.80
1-.75
2-.90
3-.90
4-.70

The struct is necessary in the program.
The program should read the reliability and print it to the screen.

This is all according to the OP.