isDigit() and isLower() for strings

[John_L]

If I were to write my own functions for single characters that would be easy. I was thinking more along the lines of strings, having overloaded functions with parameters char* or char[] for the strings. How could I tokenize the word by each character and analyze each one by itself to determine if these functions would return true or not?

[matsp]

overloading is something you can do in c++. But there's nothing preventing you from creating a function that takes a string, called something different from the one that takes a single char, that returned whether the entire string is for example digits or lower case chars.

--
Mats

[Dino]

Like this:

#include <stdio.h>

int strIsdigit(char * data) { 
	int i = 0 ; 
	while (1) { 
		if ( data[i] == '\0') return 1 ; // true - the string is all digits 
		if ( !isdigit(data[i])) return 0; 
		i++ ; 
	}
	return 1 ; 
}

int main (int argc, const char * argv[]) {
	char num1[] = "0123456789" ; 
	char num2[] = "1232abc" ; 
	char yes[] = "Yes" ; 
	char no[] = "No" ; 
	char * answer1, * answer2 ; 
	answer1 = strIsdigit(num1) ? yes : no ; 
	answer2 = strIsdigit(num2) ? yes : no ; 
    printf("&#37;s is all digits? %s\n", num1, answer1 ) ;
    printf("%s is all digits? %s\n", num2, answer2 ) ;
    return 0;
}

Todd