Thread: array inside struct

im having a problem getting this to work. the array....

Code:

struct airline {
        int seats[11] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 } ;
       char  * customer;

};

this is what i get:

Code:

9 C:\Dev-Cpp\airlines.c [Warning] no semicolon at end of struct or union 
9 C:\Dev-Cpp\airlines.c syntax error before '=' token 
12 C:\Dev-Cpp\airlines.c syntax error before '}' token

when i try int seats[11]; it works fine..
what can i do? thx

Code:

struct airline {
        int seats[11] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 } ;
       char  * customer;

};

You are creating a new data type first. Onces you've told your compiler what that new data type is all about, you can create a variable of that new type and initialized it. If you want to go even the extreme, you can declare that new variable, right after the definition of that new type:

Code:

struct airline{
    int seats[11];
    char  *customer;
}flight = { { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 } }; /* This is a partial initialization since nothing is done for the pointer customer */

BTW, if you want to store 12 elements in the array; the subscript should be the same amount.

ok i think i solved the problem
what i did

Code:

struct airline {
        int seats[12] ;
       char  customer;
};

int main(int argc, char *argv[])
{
    struct airline seat[12] = { 1,2,3,4,5,6,7,8,9,10,11,12 };

this seemes to work just fine! =)

You need to separate declarations and definitions, initializations.
First, you must tell the compiler how the actual struct looks like - ie, no initialization. Just tell the compiler how the struct looks like, how the array looks like, and so on.
When creating an object of that struct type, THAT is where you need to put the data you want into the struct.
I hope that makes sense, because it's exactly what Aia did.

Originally Posted by Elysia

You need to separate declarations and definitions, initializations.
First, you must tell the compiler how the actual struct looks like - ie, no initialization. Just tell the compiler how the struct looks like, how the array looks like, and so on.
When creating an object of that struct type, THAT is where you need to put the data you want into the struct.
.

is this what you mean?

Code:

struct airline {
        int seats[12];
       char  customer[BUFSIZ];
};


char showmenu ( void );  // proto functions  //
void shownumber ( struct airline nos );

int main(int argc, char *argv[])
{
    struct airline seats[12] = { 1,2,3,4,5,6,7,8,9,10,11,12 };

also i want to pass in the array of seats to a function so i can print it out!
how can i do this.. it dont work i get a
error of
31 C:\Dev-Cpp\airlines.c incompatible type for argument 1 of `shownumber'

Code:

struct airline {
        int seats[12];
       char  customer[BUFSIZ];
};

/**********************************************/
char showmenu ( void );  // proto functions  //
void shownumber ( struct airline nos );

/*******************************************/

/******************** MAIN******************************/
int main(int argc, char *argv[])
{
    struct airline seats[12] = { 1,2,3,4,5,6,7,8,9,10,11,12 };

       
    char choice;
    
while ( ( choice = showmenu() )!= 'f' )    // loop for menu
    {
        switch ( choice )
        {
          case 'a' : shownumber ( seats );
               break;
          
          case 'b' : printf(" you hit b");
               break;
          }
  
  system("PAUSE");	
  return 0;
}
}
/*********************** MENU FUNCTION *****************************/

char showmenu ( void )  
{
  char ans;
  printf(" ********** Welcome to Swift Lines Airlines ************\n");
  printf("\n ********** To Choose A Function, Enter its Letter Label:\n");
  printf("\na ) Show Number of seats\n");
  printf("b ) Show List of seats\n");
  printf("c ) Show alphabetical list of seats\n");
  printf("d ) Assign a Customer to a seat assignment\n");
  printf("e ) Delete a seat assignment\n");
  printf("f ) Quit\n");
  
  ans = getchar();
  ans = tolower( ans );
  
  while ( strchr ( "abcdef" , ans ) == NULL )
  {
        puts( " please pick a - f :\n");
        ans = tolower( getchar() );
        }
  return ans;
}     
/********************** END MENU FUNCTION *************************/
  
void shownumber ( struct airline nos[] )
{
     int x;
     for ( x = 0 ; x < 12; X++ )
     {
   printf ( " swift Lines seats-- %d" , nos->seats );
}
}

OK, first do you want an actual array of the struct or simply initialize the array INSIDE the struct? You're creating 12 instances of the struct currently.
Also, take a look at your declaration of the shownumber function. It doesn't match with your definition.

Originally Posted by Elysia

OK, first do you want an actual array of the struct or simply initialize the array INSIDE the struct? You're creating 12 instances of the struct currently.
Also, take a look at your declaration of the shownumber function. It doesn't match with your definition.

i wanted to initialize the array inside the struct then pass that array to a function to print it..

Originally Posted by tat

i wanted to initialize the array inside the struct then pass that array to a function to print it..

Code:

#include <stdio.h>

struct airline {
        int seats[12] ;
       char  customer;
};

void printing( int *seat, int size );

int main(int argc, char *argv[])
{
    struct airline seat = { { 1,2,3,4,5,6,7,8,9,10,11,12 } };
    
    printing( seat.seats, sizeof seat.seats / sizeof ( int ) );
    
    
    getchar();
    return 0;
 
}
void printing( int *seat, int size )
{
	int i = 0;
	
	for ( i = 0; i < size; i++ )
	{
		printf( "%d ", *( seat + i ) );
	}
}
/* output:
1 2 3 4 5 6 7 8 9 10 11 12 */

IF you have a struct, then I don't see why you shouldn't pass the entire struct instead of passing all members separately. And since there's only ONE struct with a static array, there's no need to pass the size of the struct either.

Originally Posted by Elysia

IF you have a struct, then I don't see why you shouldn't pass the entire struct instead of passing all members separately.

I tried to do that..