Thread: A begginer writing a text based dungeon game.

This will be the first of many questions to come
This is an assinment so dont give me code i won't understand becouse i wont use it, even if you give me code i understand i still won't use it but i will learn from it.

in this code i am trying to get a specific number to print out when the user types n, e, s, or w.
for example: n would be 1, and e would be -1.
all it dose is give me some strange error called signal 10 (sigbus) then it pulls up a debugger window sorry if this sounds to common it's never happend to me before.

Code:

#include <stdio.h>
#include <stdlib.h>
int main(void)
{
int room0[4]={1,2,-1,-1};
char i;

char n=0;
char s=1;
char e=2;
char w=4;



printf("number...err letter:");
      scanf("%c\n",i);

printf("print the god dam numb. %i",room0[i]);


	

	return 0;
}

please before reading whats below, can you answer the above question first even if it will not help me with the game, it's how i learn things,i am very new at this got no experience at all.

as for the text base game this is how its planned, so far i am planning to have 4 rooms and am writing the code in 4 parts, 1 for each room it sounds tedius but i just want to get from 1 room to the other for right now. the rooms have numbers 0-3, you get from each room by pressing n,s,e,w. if you try to go the wrong way its a -1. i am thinking the use of arrays, if else statements and goto statment. if there is more things i should or not use don't be shy speek up.

and now for my stupid questions

1)can you get an array of letters to equal an array of numbers.
i guess that will be it for now i will post more questions as soon as they become more prevalent to the main question.

lastly you are all probably wondering what text i am using, well i am using Programming in C third edition Stephen G. Kochan Developer's Library

scanf("%c\n",&i);

so how are you going to change that code to your code?

Originally Posted by deadherorising

1)can you get an array of letters to equal an array of numbers.

what do you mean?

Originally Posted by robwhit

scanf("%c\n",&i);

so how are you going to change that code to your code?

what do you mean?

thanks, first question: i am not sure what your talking about. i hope i did it.
but i changed the code a little. now for some resign every thing equals 1
and i changed every thing to int values.

Code:

#include <stdio.h>
#include <stdlib.h>
int main(void)
{
int room0[4]={1,2,-1,-1};
int i;
int g=room0[i];
int n=0;
int s=1;
int e=2;
int w=4;

printf("number...err whatever:");
scanf("%i\n",&i);

printf("print the god dam numb. %i",g);


	

	return 0;
}

and for my stupid question,
i mean somthing like this

int room[4]={1,2,3,4}
int die[4]={'n','s','e','w'}

int die[]=room[]

and now for my second stupid question
2) can i make an array of letters equal to letsay 0-3 using the for loop.

Originally Posted by robwhit

Code:

int room0[4]={1,2,-1,-1};
int i;
int g=room0[i]; //i is not initialized.

> int die[]=room[]
what would this do?
> 2) can i make an array of letters equal to letsay 0-3 using the for loop.
you mean an array of chars?

char arr[4] = {0,1,2,3};

what do you mean i is not initialized i is initilized right above it with int i;

1) int die[]=room[], i was hoping they would equal each other i guess not, dam.

2) ya an array of chars!
"char arr[4]={0,1,2,3}"
i thought that would just ment that there are 4 places 0=0 1=1 2=2 3=3.
i want in this case n=0 s=1 e=2 w=3.

> what do you mean i is not initialized i is initilized right above it with int i;
that's declared. int i=5; is initialized.
>1) int die[]=room[], i was hoping they would equal each other i guess not, dam.
nope, have to do a loop to do that.
> i want in this case n=0 s=1 e=2 w=3.
sounds like you want a map.

like this?

arr[n] == 0
but not
arr[0] == n

there's not an easy way to do maps in C.

Originally Posted by Salem

> 1000 x 1000 x 30
30Mbytes of storage (at least).

But that's just the tip of the iceberg, you've got to initialise all those locations with meaningful data, unless you have a lot of

N
There is ocean here
N
There is ocean here
N
There is ocean here
N
There is ocean here
N
There is ocean here

Not only that, no user will ever visit every location in your RPG, it would simply take too long (1 room per second for almost a year, non-stop)

Your RPG will have at most a few hundred locations (that are interesting in some way). I suggest you store the connectivity of the locations within the data, then you only need to store the locations which interest you

Perhaps something like this

Code:

enum { NONE, KITCHEN, HALL, STAIRS };
enum { NORTH, SOUTH, WEST, EAST };

struct room {
    char    *name;
    int      next[4];   // N,S,W,E from this location
} rooms[] = {
    { "None" },
    { "Kitchen",    { NONE,    HALL,   NONE, NONE } },
    { "Hall",       { KITCHEN, STAIRS, NONE, NONE } },
    { "Stairs",     { HALL,    NONE,   NONE, NONE } },
};

If you have
int room_num = KITCHEN;

Moving south is just
room_num = rooms[room_num].next[SOUTH];

humm interesting i see some things but i deont see others like
were dose the north south east west become initilized, is he even using them, or is he just using the hall ,kitchen and stairs as the directions.

still this dose not answer my question, how do i make a variable equal to the index.

so i should get all the numbers to work first and add all the data first than worry about adding the north south east weast, and other descriptions later. ok thanks

ok heres what i got you have 4 directions for the index if you try to type in something higher than whats inside the array my message will pop up and the program will end,

Q:what do i type to get the program to start over again from the top ?

Code:

#include <stdio.h>
#include <stdlib.h>
# define direct_max 3
int main(void)
{
int room0[direct_max]={1,2,-1,-1};
int i;

printf("number please, later it will be direction:");
scanf("%i",&i);

if (i>direct_max)
	{
	printf("you have to type n,s,e,w for you directions nothing else will work.");
	return 1;          /// i have it end here if you dont type 0,1,2,3. 
	}
		
	printf("print the god dam numb. %i",room0[i]);  
            ///it prints the number corresponding the array.
 

	return 0;
}

okay this is my very simple map it consist of one room and 4 directions you can use but you cant go any were. right now the directions are in number form. so how do i make it so when you type the wrong number it asks for a number again.

ok heres what i got :

right now the user types a letter and it prints out the index number then it prints out one of the numbers in the array. but i am getting more than what i wanted. this is what it actually dose.

direction n,s,e,w: n <---user prints letter in this case i printed an "n"
no type n,s,e,w
no type n,s,e,w
no type n,s,e,w
index number please:0
print the god dam room numb. 1
assinment 4 has exited with status 0.

it prints the right number but it keeps on going with the else statments.
first question

1) how do i make it continue to ask me for the direction when i imput a letter that is not n,s,e or w.

2)how do i stop the repeating "no type n,s,e,w" from the else statment.

3) and if i wanted to end the program when the user typed end, using an if statment what do i put in the statment.

Code:

#include <stdio.h>
#include <stdlib.h>
# define direct_max 4
int main(void)
{
int room0[direct_max]={1,2,-1,-1};
int i;/*number*/
char a;/*letter*/ 


printf("direction n,s,e,w:");
scanf("%c",&a);

	if(a=='n')
		{
		i=0;
		}
		else
			{
			printf("no type n,s,e,w\n");
			}
	if(a=='s')
		{
		i=1;
		}
		else
			{
			printf("no type n,s,e,w\n");
			}
	if(a=='e')
		{
		i=2;
		}
		else
			{
			printf("no type n,s,e,w\n");
			}
	if(a=='w')
		{
		i=3;
		}
		else
			{
			printf("no type n,s,e,w\n");
			}
			
			
printf("index number please:%i\n",i);



		
	printf("print the god dam room numb. %i",room0[i]);


	return 0;
}