heres my problem i am Initializing an array of 3 strings... i know how to initialize an array with one string.
however i have a 2d array, and i need to initialize 3 strings into it is the only way to so it like this.Code:char foobar[6] = "marry";
is there a quicker way to do this?Code:char foobar[3][9] { {'s','i','x','\0'}, {'t','w','e','l','v','e','\0'} ........................ };
Yes,
Or at runtime,Code:char foobar[3][9] = { {"six"}, {"twelve"}, {"seven"} };
Code:strcpy(foobar[0], "six"); strcpy(foobar[1], "twelve"); strcpy(foobar[2], "seven");
Last edited by zacs7; 10-24-2007 at 06:23 PM.
Good solution...
yea thats awesome!! i tried something similar to your first suggestion but kept getting a run time error! your solution is prefect! thankyou very much! Zacs7!
Just so you know, you can leave off the inner braces. Most compilers warn you about this, however, and I don't recommend doing it myself; but you sometimes see other people's code that does this, and if you don't know that you can do this it can be very confusing.
I'm not sure what standard this is, if any, but gcc gives a warning with -ansi, so it's probably not C89. Don't use it, it's just a curiosity.Code:int num[3][3] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
dwk
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Your braces should match the structure of the data you're trying to initialise, if you want to be really good about it. Some compilers / tools will complain.
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