I'm not sure if I understand you correctly, but if you want to convert int to displayable binary, one quick approach would be to store remaining parts of division (which is either 1 or 0) in char array, eg.

Code:
int i = 0;
while ( num > 0 ) { // num == int that'd be converted to binary
  if ( num % 2 == 0 ) 
      charArray[i] = '0';
  else 
      charArray[i] = '1';
  num /= 2;
  i++;
}
...and then simply reverse array and print output.