Thread: Writing hex nums from console input to string

Originally Posted by Hawkin

But how can I fill a memory location with 0x48 when I type "48", instead of 0x34 (4) and 0x38 (8)?

You want to break the string into little groups of two digits each, and convert from hex representation. Try this:

Code:

unsigned int val;
int scanned;
do
{
    scanned = sscanf(string, "%2x", &val);
    if(scanned == 1)
    {
        /* Go to the next pair of digits */
        string += 2;
        /* Successfully read a value -- do something with it */
    }
} while(scanned == 1);

And also, a bit offtopic, it's long time ago I programmed with sockets (in windows), when I use winsocks send(socket, buf, length, flag), will zero bytes within <length> bytes also be sent or will the packet truncated if it finds a zero termination?

The zero byte is ONLY special for C strings and C string processing functions. You don't have to worry about it with send().

Thank you, that was exactly what I needed

Originally Posted by Hawkin

Thank you, that was exactly what I needed

Beware that the code I posted is NOT robust against errors. If you have whitespace in your string, it will break. If the string is not an even number of characters, it will break. If there is an invalid hexadecimal digit in the string, it will stop processing when it hits it.

But hopefully it gives you the idea.

Yes I know (and experienced) that you can easily cause errors. But I only needed it and will need it for testing and debugging purposes. The original client has hardcoded packets and will change the content with normal string input and does check for several possible errors.