help with loops please

**jlaprade** · 10-05-2007

im trying to get this to run a scan of user enterd stats then calculate the body mass index's of the height in increments of 3 inches with weight in increment of 10's and say whether they are statistically overweight, like this :

5 3 150 26.5684 overweight
5 3 160 28.3396 overweight
5 6 140 22.5941 not overweight
5 6 150 24.2080 not overweight

here is what i have, but i cant find the errors is compiles in lines 66 and 107, any help would be greatly appreciated

Code:

#include <stdio.h>
#include <math.h>

int main()
{
  
int i,  /* inches variable2  */

    loheightfeet, /* low height in feet and inches*/

    hiheightfeet,  /* high height in feet and inches*/

    loweight,      /*  low weight in pounds */

    hiweight,       /*  high weight in pounds */

    inches;       /* height in inches */

  float bmi;      /* bmi */



  /* get height and weight */

  printf("Please enter low height in feet: ");

  scanf("%d", &loheightfeet);

  printf("please enter high height in feet: ");
  
  scanf("%d", &hiheightfeet);

  printf("Please enter low weight in pounds: ");

  scanf("%d", &loweight);

  printf("Please enter high weight in pounds: ");

  scanf("%d", &hiweight);
  
 
   for( i=inches, i<= hiheightfeet * 12, i=i+3){
       
              

    printf(" %d/12    %num         ", inches);   



      while( loweight <= hiweight ) {



        /* calculate BMI */

        inches = loheightfeet * 12;
 
        bmi = 703.0 * loweight / (float) (inches * inches);
    

        /* add 5 to loweight */

        loweight = loweight +10;
    



        /* indicate whether user is overweight */

          if (bmi > 25.0) {

            printf(" %d        %.4f        overweight.\n", loweight, bmi);
          }

          if (bmi < 25.0) {

            printf(" %d        %.4f       not overweight.\n", loweight, bmi );
 
   
          } 
    
       } 
            
            printf("/n")
    } 
   return 0;
}

**jlaprade** · 10-05-2007

the main problem is the for loop, is there something wrong with it?

**hk_mp5kpdw** · 10-05-2007

Code:

int loheightfeet, /* low height in feet and inches*/

    hiheightfeet,  /* high height in feet and inches*/

    loweight,      /*  low weight in pounds */

    hiweight,       /*  high weight in pounds */

    inches;       /* height in inches */

float bmi;      /* bmi */



  /* get height and weight */

  printf("Please enter low height in feet: ");

  scanf("&#37;d", &loheightfeet);

  printf("please enter high height in feet: ");
  
  scanf("%d", &hiheightfeet);

  printf("Please enter low weight in pounds: ");

  scanf("%d", &loweight);

  printf("Please enter high weight in pounds: ");

  scanf("%d", &hiweight);
  
 
   for( i=inches, i<= hiheightfeet * 12, i=i+3){

Where is inches ever initialized? And yes, you've got a problem with the for loop besides the uninitialized inches variable, those commas should be semicolons.

May be some other things but I just took a very quick glance.

**dwks** · 10-06-2007

Double-spacing your source code does not make it any easier to read. In fact, in my opinion it makes it even harder to read. (If this is because you switched line endings, then you can't help it, though.)

Code:

printf("/n")

No doubt you mean \n, not /n. And you need a semicolon after that statement as well.

Code:

        /* add 5 to loweight */

        loweight = loweight +10;

5, 10, what's the diff?

Code:

          if (bmi > 25.0) {

            printf(" &#37;d        %.4f        overweight.\n", loweight, bmi);
          }

          if (bmi < 25.0) {

            printf(" %d        %.4f       not overweight.\n", loweight, bmi );
 
   
          }

So if bmi is exactly 25.0, the user isn't even granted a message? I suggest using an else clause.

Code:

    printf(" %d/12    %num         ", inches);

Percent signs (%) have special meanings with printf(). If you meant to print a literal %, use %% -- because while %n is a valid (if uncommon) format specifier, it requires that you pass another argument to printf() to use it.

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