Thread: Need help converting a C function to PHP

Hello,

I need some help converting a C function to PHP. I know what it can do, but I can't seem to think of how to write the function in PHP. Here is the function in C:

Code:

u32 setver(u8 *gamever) {
    int     v1  = 0,
            v2  = 0,
            v3  = 0,
            v4  = 0;

    sscanf(gamever, "%d.%d.%d.%d", &v1, &v2, &v3, &v4);
    return(((v1 & 0xf) << 28) | ((v2 & 0xf) << 24) | ((v3 & 0xffff) << 8) | (v4 & 0xff));
}

The function is supposed to convert a game's version number into a 32bit hex string. So a sample game version is 1.1.2965-797.0, and you have in it n1.n2.n3.n4. And this string correctly converted to its 32bit hex form should be 110b9500 (1.1.0b95.00).

On n3, you have 0b95 which is 2965 in hex, so I think the function is written so the -797 is ignored for that specific game version, but I'm not quite sure.

Probably pretty simple for you guys . I thought I would try here first to see if anyone knows, and if not I can try a php forum too. Thanks!

Originally Posted by zacs7

I don't understand how this is related to C? You're going from C to PHP not from PHP to C.

Yea, probably a bad choice for a forum, sorry. I'll probably head over to phpfreaks or something and ask if I can't get it from this point.

However your code looks like a good start, and I can play with the return line and see if I can get the result I'm looking for. Thanks for the help

Alright thanks, your code helped! I ended up getting the rest:

Code:

function setver($gamever)
{
	$v = array(0, 0, 0, 0);
	sscanf($gamever, "%d.%d.%d.%d", $v[0], $v[1], $v[2], $v[3]);
	$decimal = (($v[0] & 0xf) << 28) | (($v[1] & 0xf) << 24) | (($v[2] & 0xffff) << 8) | ($v[3] & 0xff);
	return(dechex($decimal));
}