Thread: Modify an single passed array element

Title basicly says what wont work. Half of the below works, I pass the whole
array to a function and it modifes and returns it as expected, but when I pass
an idividual array element it display it oddly then returns the wrong value but
the correct element if that makes sense.

Output I get is: passed array element: 816 ( where is should say 8 )
modified array element: 8

I gather my problem is possibly how I am outputing the displayed array element.
I get no compile errors, its a logical error I cant faddle out but its proberly
somthing really simple

Code:

#include <stdio.h>

#define ARRAY_SIZE 5

/*function prototypes*/
void changeArray ( int, int[] );
void changeElement ( int );

/*main function - begins program execution -----------------------------------*/
int main ( void )
{
   int i, j;

   /*create and display original array*/
   int data[ ARRAY_SIZE ] = { 1, 2, 3, 4, 5 };

   printf("Original array:\n\n");

   for ( i = 0; i < ARRAY_SIZE; i++ )
   {
      printf("%d ", data[ i ]);
   }

   /*pass array size and name to function*/
   changeArray ( ARRAY_SIZE, data );

   /*output modified array output*/
   printf("\n\nModified array\n\n");

   for ( j = 0; j < ARRAY_SIZE; j++ )
   {
      printf("%d ", data[ j ]);
   }

   /*output original array element*/
   printf("\n\nOrginal array element data[ 3 ]:\n\n");

   printf("%d", data[ 3 ]);

   /*pass element to function*/
   changeElement ( data[ 3 ] );

   /*output modified array element*/
   printf("\n\nModified array element data[ 3 [:\n\n");

   printf("%d", data[ 3 ]);

   getchar(); /*freeze console output window*/

   return 0; /*return value from int main*/
}

/*function to modify and return array*/
void changeArray ( int size, int x[] )
{
   int i;

   for ( i = 0; i < size; i++ )
   {
      x[ i ] *= 2;
   }
}

/*function ro modify and return array element*/
void changeElement ( int e )
{
   printf("%d", ( e *= 2 ));
}