OK, thanks. Turns out the new code is:
Code:
void Push(struct node** headRef, int data) {
struct node* newNode = malloc(sizeof(struct node));
newNode->data = data;
newNode->next = *headRef; // The '*' to dereferences back to the real head
*headRef = newNode; // ditto
}
void PushTest() {
struct node* head = BuildTwoThree();// suppose this returns the list {2, 3}
Push(&head, 1); // note the &
Push(&head, 13);
// head is now the list {13, 1, 2, 3}
}
I think the thing that tripped me up was the **. I guess you need to know that the same rules apply as with the single *. Thanks for the help