Thread: Problems with sscanf()?

Originally Posted by killiansman

Code:

    while(sscanf(argv[1][i],"%[^.]",&c)&&check!=0)

I'm not sure what you're trying to do there: load the next char of argv[1] into c? There's no need to use sscanf() for that:

Code:

while( (c = argv[1][i]) != 0 && check != 0)

And I have no idea what that %[^.] thing is.

I forgot to say that i declared "c" as a type char. What I'm trying to do is determine if the file extension matches the expected one. Therefore, the "[^.]" simply reads up to where it encounters a period. I don't know if this can be done using sscanf() though; I know it works fine with fscanf().

Originally Posted by killiansman

I forgot to say that i declared "c" as a type char. What I'm trying to do is determine if the file extension matches the expected one. Therefore, the "[^.]" simply reads up to where it encounters a period. I don't know if this can be done using sscanf() though; I know it works fine with fscanf().

If you are checking the file extension, maybe try something like this:

Code:

char *ext;

ext = strrchr(argv[1], '.');
if(!ext)
{
    /* File has no extension */
}
else
{
    if(strcmp(++ext, "foo") == 0)
    {
        /* File has the proper extension */
    }
    else
    {
        /* Extension isn't right */
    }
}

The call to strrchr() locates the last "." in the string. If one is found, it goes to the next character, i.e., the beginning of the extension. It then compares this with the extension you are looking for ("foo" in my example).

This works because the extension is already at the end of the string, so it is null terminated.

Thanks a lot guys (or girls)... I appreciate it.