Printing characters not in the ASCII table
I am wrining a program to print a report, and I need to display the pound-sign character (£) on this report. Each instance of this character prints out as a space (I am using the fprintf() function to print). I assume this is because the character is not in the ASCII table. How can I print this character? Do I need to include a certain header file?
It's char # 156 I think...Code:#include <stdio.h> int main () { int c; int i; // There are 256 ascii characters, from 0 to 255. // A lot of the values just can't be displayed. For example, there is // the newline character, a backspace character, a tab character, and // probably the most entertaining one, the beep character. for (c = 0; c < 256; ) { // Adjust the stopping value for i accordingly. for (i = 0; i < (80) / 7 && c < 256; i++, c++) { printf ("%3d %c ", c, c); } // Depending on stopping value, this may or may not be commented out. printf ("\n"); } return 0; }
Callou collei we'll code the way
Of prime numbers and pings!
According to my old (yet trusty) ASCII chart, the pound symbol has a decimal value of 156. However, my computer uses Unicode instead of ASCII. I used this program to show me all of the symbols available with my font:
You may be experiencing a similar problem, where your system's font doesn't use extended ASCII.Code:#include <stdio.h> int main(void) { unsigned char c; for ( c=0; ; c++ ) { printf( "%03d %c\n", c, c ); if ( c == 255 ) break; } return (0); }
Jason Deckard
