need help about char

[munna_dude]

hi all
how can i truncate this...
1.2M /eee/uuu/123rwewv.zip

in this i want only "1.2M"
and
i want only 123rwewv.zip(must be after last "/")

can you help me please

thank you in advance

[ulillillia]

Perhaps you could try splitting the string into 2 separate components. I don't know how this could be done though (my known method is highly inefficient).

[mike_g]

is the text at 1.2M always going to be 4 characters? If so you could just copy the first 4 characters.

To get the end part of the string you could:
Get the line length.
Read backwards through the line until you reach the first / and save the index
Copy the section of that string after the index.
Concatenate it to the first part of the string you copied.

[Salem]

strchr() to find the first /
strrchr() to find the last /

[vart]

using strchr and strrchr you can locate start and end of substrings you need and then
strcpy for the last part and strncpy for the first

[munna_dude]

strchr() to find the first /
strrchr() to find the last /

sorry i did but, having some confusion..
i tried like this
char *s5, *split1, *file;
//file is the above file path.
s5=strrchr(file,"/");
strcpy(split1,s5);

can you please coding for me..

and also i wanna read first five char... of the path.(1.2M /eee/uuu/123rwewv.zip)

thank you in advance

[zacs7]

can you please coding for me..

Sure, we'll tell you when it's done... And while your waiting you could read the rules ?

[Salem]

> s5=strrchr(file,"/");
1. This generates some kind of error message right, something about pointer to int conversion?
Use single quotes.

Post actual code and error messages, not "something like these snippets"

> strcpy(split1,s5);
Where is split1 allocated?
Is it allocated at all?