Thread: Finding the smallest value

yeah actually i have changed the array sorting by replacing this element array[0] with the smallest one
i didn't mean to
and i guess it like itsme86 code
and he is right in "That only works because the smallest value in the array happens to be the first element"
i tried this
so
"Assign the first element of array to minimum_value" i guess i didn't get that

Code:

#include<stdio.h>
int main()
{

int x;
int smallest;
int array[]={33,33,4563,2,545645,64566,55456,4456,645645,445,65,54,65,456454};
    for(smallest = array[0], x = 1;x < 14;++x)
      {       
            if(array[x] < smallest)
               {
                    smallest = array[x];
                }
     }
   printf("The Smallest Value In The Array Is &#37;d",smallest);

return 0;
}

this works
thanks itsme86
i was wrong in x>14 it should be x<14 but i didn't see this

. That's why standard library functions which act on arrays are always written to be able to handle empty arrays

Try passing an "empty array" to strlen() and tell me what happens.

> Try passing an "empty array" to strlen() and tell me what happens.
You mean a C string with just a single '\0'? Because strlen() acts on C strings, not general arrays, and it assumes that the trailing '\0' is there. For a valid example, try calling something like qsort() or bsearch() with an empty array.

Edit: Or any of memcpy(), memmove(), memcmp(), memchr(), or memset(), since these act on character arrays, not C strings, and the length of the array is passed as an argument.