Thread: 1D-oscillationg w. energy-loss

  1. #1
    Registered User
    Join Date
    Apr 2007

    Unhappy 1D-oscillationg w. energy-loss

    the particle should go forth and back and each time he's reaching the wall (+1;-1), he should loss velocity, hence energy! But this results in incomensurability = the new dx doesn't fit into the intervall [-1;1]; here's the code:
    double x=0.0;
    	double  vx=0.43; 
    	int i , frac=7 ;
    	double tx=fabs(1/vx);
    	double dx=vx*tx/frac;
    	for (i=0 ; i<=N ; x+=dx , i++)
    	printf("%i	%.4f\n",i,x);
    	fprintf(f_ptr,"%i %.4f\n",i,x);
    	if(x<-0.99 || x>0.99)

  2. #2
    and the hat of int overfl Salem's Avatar
    Join Date
    Aug 2001
    The edge of the known universe
    > dx*=-1.0;
    How about

    > if(x<-0.99 || x>0.99)
    Or maybe make the limits a variable as well.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

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