Hey guys with the above code why does that get the character 'c' from "cat" i dont understand the pointer to another pointer?Code:putchar(**(wp+1));
Code:int main (void) { char words[5][8] = {"the","cat","in","the","hat"}; char *wp[5]; int i=0; for(i=0; i<5; i++) { wp[i] = words[i]; } puts(*wp); puts(*(wp+2)); puts(*(wp+3)+1); putchar(**(wp+1)); return EXIT_SUCCESS; }
wp is an array of pointers. This means wp can be viewed as a pointer to a pointer in one context or another.
A variable just contains a value of a certain type. A pointer contains the address of a variable of a certain type. A pointer to a pointer contains an address of a pointer of a variable of a certain type. And so on.
If wp is interpreted as a pointer, then it will be pointing at the first element of its array. This means it'll be resolved as the address of the string "the" from the array words, just as if you used wp[0] instead of (*wp). Since you're adding 1 to wp inside the function call, it'll be pointing to the next string, "cat", because (*(wp+1)) is just like having wp[1]. This means you only have a pointer to the string "cat". Dereferencing that one further means it'll also point at the first element of that array, which is the 'c' in "cat".
I typed this up kind of quickly, so I might have hurried over some things I should have paid more attention to, but I hope this gives you an idea of how it works.
ahhh k kewl
