Thread: element ?

  1. #1
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    Question element ?

    I have a question about the elements of A in the following:
    Code:
    int Tally(float A[], int Size, float X)
    {
        if (Size <= 0){     /* to see if it is 0 or neg numb and returns a*/
           return a;}
        else
           return (A[0] == X) + Tally(A + 1, Size - 1, X); /*first element is checked against X and tally a is incremented by on size decremented*/
    }

    Doesnt this code return the number of elements in A equal to x

  2. #2
    Lurking whiteflags's Avatar
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    No you'd need something like:

    return (A[0] != X) ? 0 : 1 + Tally( A + 1, Size - 1, X );

    in this way, Tally always completes the recursion.

  3. #3
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    Does it return the number of elements in a then?

  4. #4
    Officially An Architect brewbuck's Avatar
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    Quote Originally Posted by matthughes View Post
    Does it return the number of elements in a then?
    It doesn't do anything, since there is no such thing as "a"

  5. #5
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    Quote Originally Posted by brewbuck View Post
    It doesn't do anything, since there is no such thing as "a"
    instead of a it was supposed to be
    Code:
     return 0;

  6. #6
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    i got it people it returns the number of elements equal to x!!!

  7. #7
    aoeuhtns
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    Quote Originally Posted by citizen View Post
    No you'd need something like:

    return (A[0] != X) ? 0 : 1 + Tally( A + 1, Size - 1, X );

    in this way, Tally always completes the recursion.
    Uh... what?
    There are 10 types of people in this world, those who cringed when reading the beginning of this sentence and those who salivated to how superior they are for understanding something as simple as binary.

  8. #8
    Woof, woof! zacs7's Avatar
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    Quote Originally Posted by Rashakil Fol View Post
    Uh... what?
    Code:
    A[0] != X
    Is an expression it evaluates to TRUE (1) or FALSE (0).

    ie, it stops recursing once A[0] is not equal to X, otherwise it continues to recurse.

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