Thread: how do i use EOF in a char array?

Hi,
I was hoping someone may be able to help me out.
I am trying to write a program which reads and prints an input of words.
It needs to hold a max of 10 words but i need use a sentinel contolled loop using the EOF (<ctrlZ> twice) so i can end it early if needed.
I have tried to use a while loop in scanf unsucessfully in the code below.

Any help would be greatly appreciated.
Cheers,
Mike.

Code:

#include <stdio.h>
#include <string.h>
main()
{
char word[10][100];
int a, x=0;


	for(a=0; a<10; a++)
		{
		printf("enter a word\n");
		scanf("%s", word[x]);
		x=x+1;
		}
		x=0;
		
	printf("the word list is:\n");	
	for(a=0; a<10; a++)
		{
		printf("%s\n", word[x]);
		x=x+1;
		}
}

Hi,
Still unsure how this works, i do not understand what you mean when you say alter string format in scanf() to be more secure. I am not sure what this code is doing, it does end the program however prints characters to the screen.

Thanks,
Mike

Code:

#include <stdio.h>
#include <string.h>
main()
{
char word[10][100];
int a, x=0;


	for(a=0; a<10; a++)
		{
		printf("enter a word\n");
		scanf("&#37;s", word[x]);
		if(feof(stdin))
		break;
		x=x+1;
		}
		x=0;
		
	printf("the word list is:\n");	
	for(a=0; a<10; a++)
		{
		printf("%s\n", word[x]);
		x=x+1;
		}
}

Code:

if(feof(stdin))
break;

This code checks your standard input stream for EOF dile char. If it finds the EOF file. It breaks the loop and comes.

Later it prints the string.

It is basically checking the input stream, thats is your keyboard. You should alse be reading why feof() shoudn't be used for breaking a loop. Read up FAQ.,

ssharish2005

thanks all,
i'll do some more reading.

Mike

thanks guys,

Huge help!!!

Mike.