Thread: help plz

ok i just decided to learn c about a week ago and have gotten through a little part of C for Dummies.....good book so far, i thought i was picking it up pretty well, until i tried to actually write something other than an example out of the book......obviously its a very simple program but i can't seem to get it right

Code:

#include <stdio.h>

int main()
{
   int a;
   int b;
   int x;
   printf("Enter a number:");
   gets(a);
   printf("Enter the number you wish to multiply it by:\n");
   gets(b);
   x=(a*b);
   printf("%d multiplied by %d equals %d\n" a,b,x);
   return(0);   
}

my compiler is saying: "[Warning] passing arg 1 of 'gets' makes pointer from integer without a cast" on lines 9 and 11 and a "syntax error before "a"" on line 13
at one time i actually got the program to run, it asked me to enter a number and when i did i got one of those pop up errors that says math.c has encountered a problem and needs to close
i'm sure its something very simple im forgetting or just don't know about yet, any help or advice would be appreciated

gets() takes a pointer to type char; you're passing an integer to gets(). scanf() can be used for what you're doing, but there are safer ways to read an integer from stdin.

I am a learner of c proggram like you form one month. I think you can use scanf
replace of get and use (&a) in brecket.

Thanks

If you're using DevC++ or a similar IDE, you might want to think about putting getch() in there so you can actually see the result without having to run it from command line.

Code:

printf("%d multiplied by %d equals %d\n" a,b,x); 
getch();
return 0;

Simple yes, but worth mentioning.

Hi ION!

Like people already said, you can't use gets() when you are reading numbers. I recommend you to use scanf(). here's the working version of your app:

Code:

#include <stdio.h>

int main()
{
 int a;
 int b;
 int x;
 
   printf("Enter a number:");
   scanf("%d", &a);
   printf("Enter the number you wish to multiply it by:\n");
   scanf("%d", &b);
   x=a*b;
   printf("%d multiplied by %d equals %d\n", a, b, x);

return(0);   
}

thanx for your help guys.......some of your replies went right over my head but i think i got some of it anyways.......tehy seein how close i was is kinda encouraging......i tried scanf(a) and scanf(b), don't guess ive read enough about that function yet, but why add '%d'??.......i thought '%d' was just a placeholder for the printf() function.......haven't gotten to pointers yet so i would've never gotten the '&a'