question on file pointers

> my output is now cannot open file
Well if you write

perror ( "Cannot open file" );

Then you get to find out more about why the file cannot be opened.

Guesses include
- it exists already and is read-only
- the directory is not writable
- something else already has the file open for writing (another stalled copy of the program?)

Quote:

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Originally Posted by s_jsstevens

my output is now cannot open file

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You said that your input is coming from a file called "input.dat" And yet the file you are actually opening (in read-only mode) is "east." Since this file probably doesn't exist, it fails. Try to get straight in your head what you're actually doing here.

Quote:

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"east"

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is there is any extension like .txt for example ? or it's binary ?

Dont forget that u are suppose to read a file called input.dat and then create a new file called east.data. Which mean that there is no east.data in the current folder.

Try reading the input.dat and then a open a new file called east.dat write mode which created a new file.

ssharish2005

Trial and error is no way to program, I suggest you think your program through and then write it. Perhaps follow: http://cboard.cprogramming.com/showthread.php?t=88495

And read the manual on regarding functions!?!?, Don't ask "How Do I use fgets()?", because a quick Google would give you the answer.