Thread: Printf a string using "string_name" (quotes)

  1. #1
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    Printf a string using "string_name" (quotes)

    Hi guys!

    I would like to printf a string using quotes e.g.

    I would like my output to be like "Hello" and not Hello.

    e.g.

    char *name = "Hello";
    printf(" "%s" \n",name);

    But i get the output :

    a.c: In function `main':
    a.c:128: error: `s' undeclared (first use in this function)
    a.c:128: error: (Each undeclared identifier is reported only once
    a.c:128: error: for each function it appears in.)
    a.c:128: error: parse error before string constant

    What shall i do in order to get "Hello" ?

    Thanks, in advance

  2. #2
    C++ Witch laserlight's Avatar
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    You have to escape the double quotes by preceding each one with a backslash, e.g., \".
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  3. #3
    Registered User Noir's Avatar
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    Or you can use single quotes to keep your strings from looking like gibberish:
    Code:
    printf( "'%s'\n", name );

  4. #4
    Lean Mean Coding Machine KONI's Avatar
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    Quote Originally Posted by g_p View Post
    char *name = "Hello";
    and if you don't know what string literals are, rather write:

    Code:
    char name[] = "Hello";
    The result is the same but it's a C string while the other is a point to a constant (read-only) string literal.

  5. #5
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    Thank you guys!

    It worked both ways!

    Thank you

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