Thread: count and print the frequency of each ASCII character

I have a question, I dont want you guys to do the work for me. I just could really use some help understand the question, and maybe you could point me in the right direction.

I want to do the work myself, but I need some help.

How would I make a program that would count and display the frequency of each ASCII character used in a string.

how can I get a count of the characters in the arrays and the % of the occurrence?


this is what i have so far

Code:

#include <stdio.h>
#include <stdlib.h>

int main()
{
int textLenght = 0; 
char textChar; 
int asciiArray[128] = {0};


int sentence[128] = {0};

printf("Enter a line of text:");
scanf("%f", &textChar);

printf("FREQUENCY TABLE\n");
printf("---------------\n");
printf("Char Count % of Total\n");
printf("---- ----- ----------\n");
while ((textChar = getchar())!= '\n') {
textLenght++; 
asciiArray[textChar]++; 
}


printf("Press any key to continue . . .\n");              
scanf("%*[^\n]");
scanf("%*c");
	getchar();			                         
	system("pause");
	exit(0);			                         
}

You're off to a good start. First, move your input gathering above your code to print the header. Then, you just have to take care of itsme86's last sentence:

Originally Posted by itsme86

Once you're done counting the characters, loop through the array and print out the character and number for any array element that has a value greater than 0.

Since you have 128 array elements, I might do a for loop from 0 to 127 (< 128). Percent is 100 * count / total (beware of integer division problems -- cast one operand to a float). The count is just the number stored at asciiArray[i].