Thread: terminating a while loop with a character

Hi, I'm trying to write a simple spell-check program where the user enters one word at a time, but I'm having trouble terminating the program when the user is finished. I would like the program to finish accepting input when they user enters a period. This is what I've got, any help would be appreciated.

Code:

#include<stdio.h>
#include<string.h>

#define SIZE 46000
#define WORD_SIZE 128

int main( void )
{
	
	// Reads linux.words into buffer array
	FILE *dict;
	dict = fopen( "linux.words", "r" );
	if( ! dict )
	{
		printf( "Failed to input linux.words\n" );
                return 1;
        }
	char buffer[SIZE][WORD_SIZE];
        int i = 0;
        while ( fgets( buffer[i] , SIZE, dict ) != NULL ) {
                i++;
        }
	
	char word[99][29];
	int j;
	
	// This for loop reads one word at a time from the user
	// and stores the words in an array to be encoded later.
	
	for( j=0; j<100; j++ )
	{
		printf( "Enter a word( . to quit )\n" );
		fgets( word[j], 31, stdin );
			if( (strcmp( word[j], "." )) == 1 )
				j=100;
		}
		
		
	return 0;
}

With this the program only takes one word and then quits.

Thanks.

Yes well

Code:

if( (strcmp( word[j], "." )) == 1 )
   j=100;

It likely has to do with this. It would be rare for word[j] to contain a string that is just a period. That is the array { '.', '\0' } and not just the character '.' like you were thinking. Something like strchr would serve your purposes better.

And while you're at it, learn how strcmp works. 1 is not a match.

Spell checker ... wow, that brings back a lot of memories. From using simple arrays to tries and the all powerful graph model to store a dictionary to finally dynamic programming and levenshtein distance to find the correct word.

This could become interesting.