Thread: Error in function declaration

Hi
In the main I have declared a variable
char string[100];

I need to construct this variable with a function and I have written the code:

Code:

char stringReceived(int sockDesc){
char unsigned c;
char tmp[100] = " ";
int i=0;
int n;
  do {
        n = recv(sockDesc, &c, 1, 0); // this function exist for client/server dialog and is not rilevant for my problem
        if (c!='\n'){
           tmp[i]=c;
           i++;}
         } while( c!='\n' );
          tmp[i]='\0';     
return(tmp);
}

In the main I call:
string = stringReceived(nSocketDesc);

When I compile the program, this error is returned:
incompatible types assignement in function stringReceived and the line number is the call.
Sure I mistake the declaration of function, but i don't be able to correct the probleni.
Can someone help me ?
Best Regards
Nick

You need to return a char* because the return value is a string, not a single char.

Originally Posted by Noir

You need to return a char* because the return value is a string, not a single char.

Please,Must I to modify my function in this way?

Code:

char* stringReceived(int sockDesc){... }

I have tried, but without result.

Bye

Yeah, that's how you do it. You say you've tried, but I can't help if you don't describe the result.

Originally Posted by Noir

Yeah, that's how you do it. You say you've tried, but I can't help if you don't describe the result.

I have solved.
My previous function return only a char.
The new solution is :

Code:

 
void stringReceived(int sockDesc,char &s){
 char unsigned c;
 int i=0;
 int n;
 do {
       n = recv(sockDesc, &c, 1, 0);
       if (c!='\n'){
          s[i]=c;
          i++;}
      } while( c!='\n' );
     s[i]='\0';     
}

and the call is:
stringReceived(nSocketDesc,myString);
myString is passed for reference.

Thank You and Best Regards
Nick