if i was reading from a text file, and would want to save the word in to array. how should i do this?
this is hard coded in the program, but if all the data from aa to ff was initially in another file, and i will need a file pointer to read them out from the text file, how can i save them in array?Code:char *buffer[]={"aa", "bb", "cc", "dd", "ee", "ff"};
Well if you knew how many words and how long the biggest word was, you could have
char buffer[6][3];
If you know how many words, but not their lengths
char *buffer[6];
If you don't know either, then
char **buffer;
Anything with a * in it will require use of malloc at some point.
It's pretty easy to go from a true 2D array to a ** pointer, once you've got the array version working. So I would suggest you start with a really simple known file and try reading those words into a 2D array you know it will fit into.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
you could use something like this and modify it to work for you
Code:int main(){ char farray[200]; int x; FILE *fp; fp = fopen("c:\\t3.txt","r"); x=0; if(fp==NULL) printf("NULL); while(fgetc(fp) != EOF){ farray[x]= fgetc(fp); printf("%c",farray[x]); x++; } getchar(); }
Last edited by KoG Metalgod; 04-10-2007 at 06:22 AM.
You rant and rave about it, but at the end of the day, it doesn't matter if people use it as long as you don't see.
People are free to read the arguments, but if the only way for you to discover gravity is by jumping off a cliff, then that is what you're going to have to experience for yourself.
Eventually, this "fast and loose" approach of yours will bite you one too many times, then you'll figure out the correct way to do things. - Salem
