Thread: Tax Calculation Help

Hey fellow programmers....

I am working on a basic tax calcualtion for a class and I am having a little trouble. I keep getting an error when trying to execute the program. I am also trying to make the program calculate and display the total amount for all three locations and not just one each time. I know there has to be a simple command I can insert to it calculates all three at one and time and displays the total. Anyone experienced programmers point out what I might be doing wrong? Thanks so much to anyone that can help.

Here is the code I have:

Code:

#include <stdio.h>//header
#include <ctype.h>//isdigit header
main()
{//start
int iResponse = 0;//town selection
float fCost;//calculation operator
fCost = 0;
printf ("\n\tThank you for using the Kudler tax calculation utility.\n");
printf ("\n\tPlease select your location to recieve your taxable total.\n");
Printf ("\n	1\tDel Mar\n");
Printf ("	2\tEncinitas\n");
Printf ("	3\tLa Jolla\n");
printf("\n	Please select your location (1-3): ");
for(;;){
	if (scanf("&#37;d", &iResponse)==0)
		break;
		{
		        puts("Invalid number, please try again");
        
        /* clear the input buffer */
        while((iResponse = getchar()) != '\n' && iResponse != EOF) {}
	
switch (iResponse)

	case 1:
		printf("\n	Welcome Del Mar Associate.\n");
		printf("	Please enter your sub-total: $");
		scanf("\n%f", &fCost);//sale sub-total
		printf("	--------------------------------\n");
		printf("	Your total tax is $%.2f\n", fCost * .0725);//in-line calculation
		printf("	The total amount owed is $%.2f\n", fCost * (1+.0725));//in-line calculation
		break;
		getchar();
		
	case 2:
		printf("\n	Welcome Encinitas associate.\n");
		printf("	Please enter your sub-total: $");
		scanf("%f", &fCost);//sale sub-total
		printf("	--------------------------------\n");
		printf("	Your total tax is $%.2f\n", fCost * .075);//in-line calculation
		printf("	The total amount owed is $%.2f\n", fCost * (1+.075));//in-line calculation
		break;
		getchar();

	case 3:
		printf("\n	Welcome La Jolla associate.\n");
		printf("	Please enter your sub-total: $");
		scanf("%f", &fCost);//sale sub-total
		printf("	--------------------------------\n");		
		printf("	Your total tax is $%.2f\n", fCost * .0775);//in-line calculation
		printf("	The total amount owed is $%.2f\n", fCost * (1+.0775));//in-line calculation
		break;
		getchar();
		}// end calc						
		getchar();//keeps application viewable on screen
	}// end selection

You need a left brace on the switch line:

Code:

  switch (iResponse) { // <- you don't have this

and the corresponding right brace afterwards. Also, you're not indenting properly at all. When writing code, always follow these two rules:

1) When you type a left brace, IMMEDIATELY type the corresponding closing right brace. Don't wait.
2) When you start typing statements after each left brace, indent them by your chosen amount of white space.

If you follow these two rules, your code will always be properly indented as you write it, and it will help you avoid mistakes.

I meant that while you're in the middle of writing code, you write the corresponding right brace a few lines down, at the same offset from the left. For example, you can start your program like this:

Code:

int main(void) {

}

Notice that I immediately type the right brace. I do NOT write the entire program and then type the closing right brace last. Of course, when you start adding lines, they go between the two braces. Now I start adding lines, each indented (I personally use 2 spaces). It doesn't matter how much you use. Just choose something and use it consistently.

Code:

#include <stdio.h>

int main(void) {
  int i;
  float j;

}

Now, if I want to add a loop, that has its own braces. So when I type the left brace, I also type the right brace:

Code:

#include <stdio.h>

int main(void) {
  int i;
  float j;
  for (i=0; i<5; i++) {

  }

}

and so on. Notice that at every step the code is properly indented. This helps prevent mistakes.

How about deleting code until you have something which compiles?

Or produces only a few error messages?

>

Code:

while((iResponse = getchar()) != '\n' && iResponse != EOF) {}

This while loop does nothing

>

Code:

switch (iResponse) { //
		}

This switch has no cases

Remember, write a bit, compile it, test it.

Not write everything, compile and get 100's of errors then dump on a message board.

Originally Posted by Cyberdine

Ok got some more bugs worked out. I need to add a loop so it calculates all three stores and shows me all three store totals. How can I or where would I add the loop to do this? I got an example but am still a little confused,

Code:

int main()
{ 
  int x = 0;  /* Don't forget to declare variables */
  
  while ( x < 10 ) { /* While x is less than 10 */
      printf( "&#37;d\n", x );
      x++;             /* Update x so the condition can be met eventually */
  }
  getchar();
}

You could do something like that, but there's an easier way - if you're game for it.

As you probably know, control "falls through" each of the cases in a switch case statement, unless it has a break statement.

So no break statements, and POOF!, it all gets printed up! Of course, we can't do something that rash, but we could add another an if statement to the bottom of each case statement, and basically tell the program "If the case is not 4, then break out".

Meaning of course, if the case IS 4, then we just want it to "fall through" to print out the next customer's info.

Code:

 

switch (iResponse) { //
		}
	case 1: case 4:
		printf("\n	Welcome Del Mar Associate.\n");
		printf("	Please enter your sub-total: $");
		scanf("\n%f", &fCost);//sale sub-total
		printf("	--------------------------------\n");
		printf("	Your total tax is $%.2f\n", fCost * .0725);//in-line calculation
		printf("	The total amount owed is $%.2f\n", fCost * (1+.0725));//in-line calculation
		if (case != 4) break;
		
	case 2: 
		printf("\n	Welcome Encinitas associate.\n");
		printf("	Please enter your sub-total: $");
		scanf("%f", &fCost);//sale sub-total
		printf("	--------------------------------\n");
		printf("	Your total tax is $%.2f\n", fCost * .075);//in-line calculation
		printf("	The total amount owed is $%.2f\n", fCost * (1+.075));//in-line calculation
		break;

	case 3:
		printf("\n	Welcome La Jolla associate.\n");
		printf("	Please enter your sub-total: $");
		scanf("%f", &fCost);//sale sub-total
		printf("	--------------------------------\n");		
		printf("	Your total tax is $%.2f\n", fCost * .0775);//in-line calculation
		printf("	The total amount owed is $%.2f\n", fCost * (1+.0775));//in-line calculation
		break;
		}// end calc						
		
                getchar();//keeps application viewable on screen
	}// end selection

Note the blue code portion above. Something like that, for all the other cases, perhaps?

Adak